What is the integral of sqrt(3x)-x ?

The integral of sqrt(3x)-x is 2/(sqrt(3))x^{3/2}-(x^2)/2+C

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integral of sqrt(3x)-x

\int 3 x - x d x

\frac{2}{3} x^{\frac{3}{2}} - \frac{x ^{2}}{2} + C

Solution steps

\int 3 x - x d x

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \int 3 x - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int x d x

\int 3 x d x = \frac{2}{3} x^{\frac{3}{2}}

\int x d x = \frac{x ^{2}}{2}

= \frac{2}{3} x^{\frac{3}{2}} - \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} - \frac{x ^{2}}{2} + C

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What is the integral of sqrt(3x)-x ?
The integral of sqrt(3x)-x is 2/(sqrt(3))x^{3/2}-(x^2)/2+C