What is the derivative of x^2-4x-4 ?

The derivative of x^2-4x-4 is 2x-4

What is the first derivative of x^2-4x-4 ?

The first derivative of x^2-4x-4 is 2x-4

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derivative of

x^{2} - 4 x - 4

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 2 x - 4 - 0

Simplify

= 2 x - 4

9 x sin (x)

\frac{d}{d x} (\frac{2 sin ( x )}{1 + cos ( x )})

\int 2^{3 x + l o g_{2} (x)} d x

- 0.1 x^{2} + 0.8 x + 9

\int \frac{e ^{a r c t a n (x)}}{x ^{2} + 1} d x

What is the derivative of x^2-4x-4 ?
The derivative of x^2-4x-4 is 2x-4
What is the first derivative of x^2-4x-4 ?
The first derivative of x^2-4x-4 is 2x-4