What is the derivative of f(x)=sqrt((x-1)/(x+1)) ?

The derivative of f(x)=sqrt((x-1)/(x+1)) is 1/(sqrt(x-1)(x+1)^{3/2)}

What is the first derivative of f(x)=sqrt((x-1)/(x+1)) ?

The first derivative of f(x)=sqrt((x-1)/(x+1)) is 1/(sqrt(x-1)(x+1)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{x - 1}{x + 1}

\frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{x - 1}{x + 1})

Apply the chain rule:

\frac{1}{2 \frac{x - 1}{x + 1}} \frac{d}{d x} (\frac{x - 1}{x + 1})

= \frac{1}{2 \frac{x - 1}{x + 1}} \frac{d}{d x} (\frac{x - 1}{x + 1})

\frac{d}{d x} (\frac{x - 1}{x + 1}) = \frac{2}{( x + 1 ) ^{2}}

= \frac{1}{2 \frac{x - 1}{x + 1}} \cdot \frac{2}{( x + 1 ) ^{2}}

Simplify

\frac{1}{2 \frac{x - 1}{x + 1}} \cdot \frac{2}{( x + 1 ) ^{2}} : \frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

= \frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

\int e^{x} \cdot arctan (e^{x}) d x

f (x) = x^{2} - 4, (5, 21)

\int (e^{7 x} - \frac{1}{x}) d x

\int \frac{4 x - 6}{x ^{2} - 2 x} d x

\frac{d ^{2}}{d x ^{2}} (e^{x^{2}})

What is the derivative of f(x)=sqrt((x-1)/(x+1)) ?
The derivative of f(x)=sqrt((x-1)/(x+1)) is 1/(sqrt(x-1)(x+1)^{3/2)}
What is the first derivative of f(x)=sqrt((x-1)/(x+1)) ?
The first derivative of f(x)=sqrt((x-1)/(x+1)) is 1/(sqrt(x-1)(x+1)^{3/2)}