What is the integral of (-x)/(x^2) ?

The integral of (-x)/(x^2) is -ln|x|+C

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integral of (-x)/(x^2)

\int \frac{- x}{x ^{2}} d x

- ln ∣ x ∣ + C

Solution steps

\int \frac{- x}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{x}{x ^{2}} d x

Cancel the common factor:

x

= - \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= - ln ∣ x ∣

Add a constant to the solution

= - ln ∣ x ∣ + C

f (x) = (x^{3} + x) (x^{2} + 2)

\int \frac{1}{x ^{2} e ^{x^{2}}} d x

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\int \frac{1}{3} x^{\frac{- 2}{3}} d x