What is the integral of sin(4x)+cos(3x) ?

The integral of sin(4x)+cos(3x) is -1/4 cos(4x)+1/3 sin(3x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(4x)+cos(3x)

\int sin (4 x) + cos (3 x) d x

- \frac{1}{4} cos (4 x) + \frac{1}{3} sin (3 x) + C

Solution steps

\int sin (4 x) + cos (3 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (4 x) d x + \int cos (3 x) d x

\int sin (4 x) d x = - \frac{1}{4} cos (4 x)

\int cos (3 x) d x = \frac{1}{3} sin (3 x)

= - \frac{1}{4} cos (4 x) + \frac{1}{3} sin (3 x)

Add a constant to the solution

= - \frac{1}{4} cos (4 x) + \frac{1}{3} sin (3 x) + C

\int \frac{1}{( 4 x + 2 ) ^{2}} d x

\int \frac{x}{( 4 x ^{2} - 5 ) ^{6}} d x

\int (e^{x} - 3 x^{2}) d x

\int 4 e^{- 2 t} + 4 d t

\int \frac{( x ^{2} + x ) ^{2}}{x - 1} d x

What is the integral of sin(4x)+cos(3x) ?
The integral of sin(4x)+cos(3x) is -1/4 cos(4x)+1/3 sin(3x)+C