What is the tangent of f(x)=x-2sin(x),\at x=0 ?

The tangent of f(x)=x-2sin(x),\at x=0 is y=-x

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tangent of f(x)=x-2sin(x),\at x=0

tangent of

f (x) = x - 2 sin (x), at x = 0

y = - x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = x - 2 sin (x) : \frac{df ( x )}{d x} = 1 - 2 cos (x)

Compute the slope of

f (x) = x - 2 sin (x)

x = 0 : m = - 1

Find the line with slope m=

- 1

and passing through

(0, 0) : y = - x

y = - x

x y^{^{''}} - y^{^{'}} = x^{2}

\frac{x - 5}{x ^{2} + 1}

\frac{d}{d x} (\frac{24}{x ^{4}})

\frac{d}{d x} (\frac{1}{5 + 3 x})

\frac{d}{d x} (5 x + \frac{7}{t})

What is the tangent of f(x)=x-2sin(x),\at x=0 ?
The tangent of f(x)=x-2sin(x),\at x=0 is y=-x