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Popular >

integral of-x^2+16

Solution

\int - x^{2} + 16 d x

Solution

- \frac{x ^{3}}{3} + 16 x + C

Solution steps

\int - x^{2} + 16 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int x^{2} d x + \int 16 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 16 d x = 16 x

= - \frac{x ^{3}}{3} + 16 x

Add a constant to the solution

= - \frac{x ^{3}}{3} + 16 x + C

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\int \frac{3 x ^{2} ( x ^{3} ) ^{2}}{5 x} d x

Frequently Asked Questions (FAQ)

What is the integral of-x^2+16 ?
The integral of-x^2+16 is -(x^3)/3+16x+C