What is the integral of 1 1/(1+x^2) ?

The integral of 1 1/(1+x^2) is arctan(x)+C

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integral of 1 1/(1+x^2)

\int 1 \frac{1}{1 + x ^{2}} d x

arctan (x) + C

Solution steps

\int 1 \cdot \frac{1}{1 + x ^{2}} d x

Simplify

= \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

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What is the integral of 1 1/(1+x^2) ?
The integral of 1 1/(1+x^2) is arctan(x)+C