What is the integral of-sec^2(y) ?

The integral of-sec^2(y) is -tan(y)+C

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integral of-sec^2(y)

\int - sec^{2} (y) d y

- tan (y) + C

Solution steps

\int - sec^{2} (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= - tan (y)

Add a constant to the solution

= - tan (y) + C

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