What is the tangent of f(x)= 7/(x^4),\at x=-3 ?

The tangent of f(x)= 7/(x^4),\at x=-3 is y= 28/243 x+35/81

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tangent of f(x)= 7/(x^4),\at x=-3

tangent of

f (x) = \frac{7}{x ^{4}}, at x = - 3

y = \frac{28}{243} x + \frac{35}{81}

Solution steps

Find the tangent point:

(- 3, \frac{7}{81})

Find the slope of

f (x) = \frac{7}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{28}{x ^{5}}

Compute the slope of

f (x) = \frac{7}{x ^{4}}

x = - 3 : m = \frac{28}{243}

Find the line with slope m=

\frac{28}{243}

and passing through

(- 3, \frac{7}{81}) : y = \frac{28}{243} x + \frac{35}{81}

y = \frac{28}{243} x + \frac{35}{81}

y = x + 2, (- 1, 1)

\frac{d y}{d x} = \frac{y ^{2} + x y + x ^{2}}{x ^{2}}, y (1) = - 1

x \to - 4 + lim (\frac{- 2}{x ^{2} - 16})

\frac{\partial}{\partial x} (ln (\frac{x}{4}))

\int \frac{32 x ^{2}}{( x - 12 ) ( x + 4 ) ^{2}} d x

What is the tangent of f(x)= 7/(x^4),\at x=-3 ?
The tangent of f(x)= 7/(x^4),\at x=-3 is y= 28/243 x+35/81