What is the integral of (3\sqrt[3]{x^4}-3) ?

The integral of (3\sqrt[3]{x^4}-3) is 9/7 x^{7/3}-3x+C

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integral of (3\sqrt[3]{x^4}-3)

\frac{9}{7} x^{\frac{7}{3}} - 3 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 3 d x = 3 x

= \frac{9}{7} x^{\frac{7}{3}} - 3 x

Add a constant to the solution

= \frac{9}{7} x^{\frac{7}{3}} - 3 x + C

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What is the integral of (3\sqrt[3]{x^4}-3) ?
The integral of (3\sqrt[3]{x^4}-3) is 9/7 x^{7/3}-3x+C