What is the integral of 5x^4e^x ?

The integral of 5x^4e^x is 5(x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x))))+C

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integral of 5x^4e^x

\int 5 x^{4} e^{x} d x

5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))) + C

Solution steps

\int 5 x^{4} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int x^{4} e^{x} d x

Apply Integration By Parts

: x^{4} e^{x} - \int 4 x^{3} e^{x} d x

= 5 (x^{4} e^{x} - \int 4 x^{3} e^{x} d x)

\int 4 x^{3} e^{x} d x = 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))

= 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x}))))

Add a constant to the solution

= 5 (x^{4} e^{x} - 4 (x^{3} e^{x} - 3 (x^{2} e^{x} - 2 (e^{x} x - e^{x})))) + C

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What is the integral of 5x^4e^x ?
The integral of 5x^4e^x is 5(x^4e^x-4(x^3e^x-3(x^2e^x-2(e^xx-e^x))))+C