What is the integral of 1/(x^{1.04)} ?

The integral of 1/(x^{1.04)} is -(25)/(x^{0.04)}+C

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integral of 1/(x^{1.04)}

\int \frac{1}{x ^{1.04}} d x

- \frac{25}{x ^{0.04}} + C

Solution steps

\int \frac{1}{x ^{1.04}} d x

Apply the Power Rule

: - \frac{25}{x ^{0.04}}

= - \frac{25}{x ^{0.04}}

Add a constant to the solution

= - \frac{25}{x ^{0.04}} + C

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What is the integral of 1/(x^{1.04)} ?
The integral of 1/(x^{1.04)} is -(25)/(x^{0.04)}+C