What is the integral of 1/(sqrt(x-8)) ?

The integral of 1/(sqrt(x-8)) is 2sqrt(x-8)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(sqrt(x-8))

\int \frac{1}{x - 8} d x

2 x - 8 + C

Solution steps

\int \frac{1}{x - 8} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x - 8

= 2 x - 8

Add a constant to the solution

= 2 x - 8 + C

\int \frac{16 - 9 x ^{2}}{2 x} d x

\int \frac{y ^{2} + 16 y + 64}{( y ^{2} + 64 ) ^{2}} d y

\int - 6 sin^{2} (x) d x

\int \frac{e ^{2 x}}{e ^{2 x} - 5} d x

\int 6 cos (3 x) sin (3 x) d x

What is the integral of 1/(sqrt(x-8)) ?
The integral of 1/(sqrt(x-8)) is 2sqrt(x-8)+C