What is the integral of-1/(sqrt(y)) ?

The integral of-1/(sqrt(y)) is -2sqrt(y)+C

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integral of-1/(sqrt(y))

\int - \frac{1}{y} d y

- 2 y + C

Solution steps

\int - \frac{1}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{y} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= - 2 y^{\frac{1}{2}}

Apply radical rule:

= - 2 y

Add a constant to the solution

= - 2 y + C

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What is the integral of-1/(sqrt(y)) ?
The integral of-1/(sqrt(y)) is -2sqrt(y)+C