What is the integral of (e^{3+ln(x)})/(-2x) ?

The integral of (e^{3+ln(x)})/(-2x) is -(e^3)/2 x+C

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integral of (e^{3+ln(x)})/(-2x)

\int \frac{e ^{3 + l n (x)}}{- 2 x} d x

- \frac{e ^{3}}{2} x + C

Solution steps

\int \frac{e ^{3 + l n (x)}}{- 2 x} d x

\frac{e ^{3 + l n (x)}}{- 2 x} = - \frac{e ^{3}}{2}

= \int - \frac{e ^{3}}{2} d x

Integral of a constant:

\int a d x = a x

= (- \frac{e ^{3}}{2}) x

Simplify

= - \frac{e ^{3}}{2} x

Add a constant to the solution

= - \frac{e ^{3}}{2} x + C

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\int 0.0006 x^{2} - 0.14 x + 21 d x

What is the integral of (e^{3+ln(x)})/(-2x) ?
The integral of (e^{3+ln(x)})/(-2x) is -(e^3)/2 x+C