What is (\partial)/(\partial y)(y/(x+z)) ?

The answer to (\partial)/(\partial y)(y/(x+z)) is 1/(x+z)

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(\partial)/(\partial y)(y/(x+z))

\frac{\partial}{\partial y} (\frac{y}{x + z})

\frac{1}{x + z}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{x + z})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x + z} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= \frac{1}{x + z} \cdot 1

Simplify

= \frac{1}{x + z}

\int \frac{2 x + 1}{x + 1} d x

f (x) = \frac{3}{x ^{2}}

\frac{\partial}{\partial x} (\frac{( a + c x )}{c + b})

\int cos (θ) sin (θ) d θ

\frac{d y}{d x} = 5 x + y - 5

What is (\partial)/(\partial y)(y/(x+z)) ?
The answer to (\partial)/(\partial y)(y/(x+z)) is 1/(x+z)