What is the integral of e^{x-5} ?

The integral of e^{x-5} is e^{x-5}+C

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integral of e^{x-5}

\int e^{x - 5} d x

e^{x - 5} + C

Solution steps

\int e^{x - 5} d x

e^{x - 5} = e^{- 5} e^{x}

= \int e^{- 5} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{- 5} \cdot \int e^{x} d x

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{5}} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= \frac{1}{e ^{5}} e^{x}

Simplify

\frac{1}{e ^{5}} e^{x} : e^{x - 5}

= e^{x - 5}

Add a constant to the solution

= e^{x - 5} + C

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