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Popular >

integral of k/(2x^2)

Solution

\int \frac{k}{2 x ^{2}} d x

Solution

- \frac{k}{2 x} + C

Solution steps

\int \frac{k}{2 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{k}{2} \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= \frac{k}{2} (- \frac{1}{x})

Simplify

\frac{k}{2} (- \frac{1}{x}) : - \frac{k}{2 x}

= - \frac{k}{2 x}

Add a constant to the solution

= - \frac{k}{2 x} + C

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Frequently Asked Questions (FAQ)

What is the integral of k/(2x^2) ?
The integral of k/(2x^2) is -k/(2x)+C