What is the limit as x approaches-1 of 1/((x+1)) ?

The limit as x approaches-1 of 1/((x+1)) is diverges

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limit as x approaches-1 of 1/((x+1))

x \to - 1 lim (\frac{1}{( x + 1 )})

diverges

Solution steps

x \to - 1 lim (\frac{1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= diverges

y^{^{'}} = \frac{y ^{2} + y x + x ^{2}}{x ^{2}}, y (1) = - 1

\frac{d}{d x} (e^{- 3 x} sin (2 x))

1 0^{8 - x^{2}}

\frac{\partial}{\partial x} ((x) (2 x y))

\frac{d y}{d x} = \frac{7 x}{4 y}

What is the limit as x approaches-1 of 1/((x+1)) ?
The limit as x approaches-1 of 1/((x+1)) is diverges