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Popular >

integral of 1/(x+12)

Solution

\int \frac{1}{x + 12} d x

Solution

ln ∣ x + 12 ∣ + C

Solution steps

\int \frac{1}{x + 12} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + 12

= ln ∣ x + 12 ∣

Add a constant to the solution

= ln ∣ x + 12 ∣ + C

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\int e^{a x} cos (m x) d x

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\int \frac{x ^{2} + 1}{x ^{2} + 1} d x

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\int \frac{sec ^{3} ( 2 x )}{tan ( 2 x )} d x

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\int x sin (7 x^{2}) d x

integral of (e^{-x}+1)^2

\int (e^{- x} + 1)^{2} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(x+12) ?
The integral of 1/(x+12) is ln|x+12|+C