What is the integral of xe^{16x} ?

The integral of xe^{16x} is 1/256 (e^{16x}*16x-e^{16x})+C

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integral of xe^{16x}

\int x e^{16 x} d x

\frac{1}{256} (e^{16 x} \cdot 16 x - e^{16 x}) + C

Solution steps

\int x e^{16 x} d x

Apply u-substitution

: \int \frac{e ^{u} u}{256} d u

= \int \frac{e ^{u} u}{256} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{256} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{1}{256} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{256} (e^{u} u - e^{u})

Substitute back

u = 16 x

= \frac{1}{256} (e^{16 x} \cdot 16 x - e^{16 x})

Add a constant to the solution

= \frac{1}{256} (e^{16 x} \cdot 16 x - e^{16 x}) + C

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What is the integral of xe^{16x} ?
The integral of xe^{16x} is 1/256 (e^{16x}*16x-e^{16x})+C