What is the integral of 3\sqrt[3]{x^4}-3x+2/x ?

The integral of 3\sqrt[3]{x^4}-3x+2/x is 9/7 x^{7/3}-(3x^2)/2+2ln|x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3\sqrt[3]{x^4}-3x+2/x

\frac{9}{7} x^{\frac{7}{3}} - \frac{3 x ^{2}}{2} + 2 ln ∣ x ∣ + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int \frac{2}{x} d x = 2 ln ∣ x ∣

= \frac{9}{7} x^{\frac{7}{3}} - \frac{3 x ^{2}}{2} + 2 ln ∣ x ∣

Add a constant to the solution

= \frac{9}{7} x^{\frac{7}{3}} - \frac{3 x ^{2}}{2} + 2 ln ∣ x ∣ + C

\int 2 sin^{3} (6 x) cos^{3} (6 x) d x

\int 3 x^{3} e^{3 x^{2}} d x

\int (\frac{1}{t} i + j - t^{\frac{3}{2}} k) d t

\int 30 sec^{4} (x) d x

\int 3 x \cdot cos (3 - x^{2}) d x

What is the integral of 3\sqrt[3]{x^4}-3x+2/x ?
The integral of 3\sqrt[3]{x^4}-3x+2/x is 9/7 x^{7/3}-(3x^2)/2+2ln|x|+C