What is the integral of (e^x)/(\sqrt[3]{e^x+5)} ?

The integral of (e^x)/(\sqrt[3]{e^x+5)} is 3/2 (e^x+5)^{2/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^x)/(\sqrt[3]{e^x+5)}

\frac{3}{2} (e^{x} + 5)^{\frac{2}{3}} + C

Solution steps

Apply u-substitution

Apply the Power Rule

: \frac{3}{2} v^{\frac{2}{3}}

= \frac{3}{2} v^{\frac{2}{3}}

Substitute back

= \frac{3}{2} (e^{x} + 5)^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{2} (e^{x} + 5)^{\frac{2}{3}} + C

\int z^{- 4} d z

\int \frac{sec ( x )}{2 tan ^{2} ( x ) + 1} d x

\int e^{- x} 9 - e^{2 x} d x

\int (3 x - h)^{3} d x

\int \frac{x}{x ^{3} + 3 x ^{2} - 9 x - 27} d x

What is the integral of (e^x)/(\sqrt[3]{e^x+5)} ?
The integral of (e^x)/(\sqrt[3]{e^x+5)} is 3/2 (e^x+5)^{2/3}+C