What is the integral of 9sec(x) ?

The integral of 9sec(x) is 9ln|tan(x)+sec(x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9sec(x)

\int 9 sec (x) d x

9 ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int 9 sec (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= 9 ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= 9 ln ∣ tan (x) + sec (x) ∣ + C

\int 6 x^{3} e^{2 x} d x

\int 7 x^{2} tan (2 x^{3} - 5) d x

\int \frac{x + 1}{( x - 5 ) ^{2}} d x

\int (\frac{x x + x}{x ^{2}}) d x

\int 8 x^{5} - 2 d x

What is the integral of 9sec(x) ?
The integral of 9sec(x) is 9ln|tan(x)+sec(x)|+C