What is the integral of sin^5(m)y ?

The integral of sin^5(m)y is (y^2sin^5(m))/2+C

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integral of sin^5(m)y

\int sin^{5} (m) y d y

\frac{y ^{2} sin ^{5} ( m )}{2} + C

Solution steps

\int sin^{5} (m) y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{5} (m) \cdot \int y d y

Apply the Power Rule

: \frac{y ^{2}}{2}

= sin^{5} (m) \frac{y ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{y ^{2} sin ^{5} ( m )}{2}

Add a constant to the solution

= \frac{y ^{2} sin ^{5} ( m )}{2} + C

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What is the integral of sin^5(m)y ?
The integral of sin^5(m)y is (y^2sin^5(m))/2+C