What is the integral of (e^{-t/6}-e^{t/6})^2 ?

The integral of (e^{-t/6}-e^{t/6})^2 is C

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integral of (e^{-t/6}-e^{t/6})^2

\int (e^{- \frac{t}{6}} - e^{\frac{t}{6}})^{2} d t

C

Solution steps

\int (e^{- \frac{t}{6}} - e^{\frac{t}{6}})^{2} d t

- \frac{t}{6} = t \frac{1}{6}

= \int (e^{t \frac{1}{6}} - e^{\frac{t}{6}})^{2} d t

(e^{t \frac{1}{6}} - e^{\frac{t}{6}})^{2} = 0

= \int 0 d t

Integral of a constant:

\int a d x = a x

= 0 \cdot t

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

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What is the integral of (e^{-t/6}-e^{t/6})^2 ?
The integral of (e^{-t/6}-e^{t/6})^2 is C