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Popular >

integral of 4^{2x-1}

Solution

\int 4^{2 x - 1} d x

Solution

8 (2 x - 1) + C

Solution steps

\int 4^{2 x - 1} d x

Apply u-substitution

: \int 8 d u

= \int 8 d u

Integral of a constant:

\int a d x = a x

= 8 u

Substitute back

u = 2 x - 1

= 8 (2 x - 1)

Add a constant to the solution

= 8 (2 x - 1) + C

Popular Examples

integral from-3 to 5 of 1/(sqrt(|x-1|))

\int_{- 3}^{5} \frac{1}{∣ x - 1 ∣} d x

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\int_{2}^{3} 1 0^{x} d x

integral from 1 to 2 of e^{-ln(x^2)}

\int_{1}^{2} e^{- l n (x^{2})} d x

integral from 0 to 1 of xe^{(x^2-1)}

\int_{0}^{1} x e^{(x^{2} - 1)} d x

integral from 0 to 5 of ti+t^2j+t^3k

\int_{0}^{5} t i + t^{2} j + t^{3} k d x

Frequently Asked Questions (FAQ)

What is the integral of 4^{2x-1} ?
The integral of 4^{2x-1} is 8(2x-1)+C