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Popular >

integral from-3 to 4 of |x+1|

Solution

\int_{- 3}^{4} ∣ x + 1 ∣ d x

Solution

\frac{29}{2}

+1

Decimal Notation

14.5

Solution steps

\int_{- 3}^{4} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 3}^{- 1} - x - 1 d x + \int_{- 1}^{4} x + 1 d x

\int_{- 3}^{- 1} - x - 1 d x = 2

\int_{- 1}^{4} x + 1 d x = \frac{25}{2}

= 2 + \frac{25}{2}

Simplify

2 + \frac{25}{2} : \frac{29}{2}

= \frac{29}{2}

Popular Examples

integral from 1 to 6 of (x^3+x^2+3)

\int_{1}^{6} (x^{3} + x^{2} + 3) d x

integral from 2 to 3 of 7/x+x^{-1}

\int_{2}^{3} \frac{7}{x} + x^{- 1} d x

integral from-1 to 0 of (2x+1)^4(x+1)

\int_{- 1}^{0} (2 x + 1)^{4} (x + 1) d x

integral from-1 to 2 of 4x+x^2

\int_{- 1}^{2} 4 x + x^{2} d x

integral from 1 to e of (ln(x))^6

\int_{1}^{e} (ln (x))^{6} d x

Frequently Asked Questions (FAQ)

What is the integral from-3 to 4 of |x+1| ?
The integral from-3 to 4 of |x+1| is 29/2