What is the tangent of y=2x-2x^2,\at x=-1.5 ?

The tangent of y=2x-2x^2,\at x=-1.5 is y=8x+4.5

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tangent of y=2x-2x^2,\at x=-1.5

tangent of

y = 2 x - 2 x^{2}, at x = - 1.5

y = 8 x + 4.5

Solution steps

Find the tangent point:

(- 1.5, - 7.5)

Find the slope of

y = 2 x - 2 x^{2} : \frac{d y}{d x} = 2 - 4 x

Compute the slope of

y = 2 x - 2 x^{2}

x = - 1.5 : m = 8

Find the line with slope m=

8

and passing through

(- 1.5, - 7.5) : y = 8 x + 4.5

y = 8 x + 4.5

y = (x + 1)^{x^{2}}, (0, 1)

\int \frac{3}{3 x + 2} d x

\int_{1}^{2} (x^{3}) d x

\frac{d}{d x} (7 - (1.01)^{- x^{2}})

f (x) = x^{2} + 1, (- 5, 26)

What is the tangent of y=2x-2x^2,\at x=-1.5 ?
The tangent of y=2x-2x^2,\at x=-1.5 is y=8x+4.5