What is the integral from 0 to 1 of (x+5)^3 ?

The integral from 0 to 1 of (x+5)^3 is 671/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (x+5)^3

\int_{0}^{1} (x + 5)^{3} d x

\frac{671}{4}

Decimal Notation

167.75

Solution steps

\int_{0}^{1} (x + 5)^{3} d x

Apply u-substitution

: \int_{5}^{6} u^{3} d u

= \int_{5}^{6} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{5}^{6}

= [\frac{u ^{4}}{4}]_{5}^{6}

Compute the boundaries:

\frac{671}{4}

= \frac{671}{4}

\int_{0}^{1} (1 - x^{2})^{6} d x

\int_{1}^{\infty} \frac{x}{x ^{2} + 9} d x

\int_{0}^{1} (1 - x^{4})^{10} d x

\int_{0}^{\frac{1}{3}} x 1 - 5 x^{2} d x

\int_{1}^{4} \frac{1}{x ^{3}} ln (6 x) d x

What is the integral from 0 to 1 of (x+5)^3 ?
The integral from 0 to 1 of (x+5)^3 is 671/4