What is the integral from-infinity to 1 of sqrt(6-x) ?

The integral from-infinity to 1 of sqrt(6-x) is diverges

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integral from-infinity to 1 of sqrt(6-x)

\int_{- \infty}^{1} 6 - x d x

diverges

Solution steps

\int_{- \infty}^{1} 6 - x d x

Compute the indefinite integral:

\int 6 - x d x = - \frac{2}{3} (6 - x)^{\frac{3}{2}} + C

Compute the boundaries:

\int_{- \infty}^{1} 6 - x d x =

diverges

= diverges

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What is the integral from-infinity to 1 of sqrt(6-x) ?
The integral from-infinity to 1 of sqrt(6-x) is diverges