What is the integral from 1 to 2 of (7x^2-57x+8) ?

The integral from 1 to 2 of (7x^2-57x+8) is -367/6

Popular >

integral from 1 to 2 of (7x^2-57x+8)

\int_{1}^{2} (7 x^{2} - 57 x + 8) d x

- \frac{367}{6}

Decimal Notation

- 61.16666 \dots

Solution steps

\int_{1}^{2} 7 x^{2} - 57 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 7 x^{2} d x - \int_{1}^{2} 57 x d x + \int_{1}^{2} 8 d x

\int_{1}^{2} 7 x^{2} d x = \frac{49}{3}

\int_{1}^{2} 57 x d x = \frac{171}{2}

\int_{1}^{2} 8 d x = 8

= \frac{49}{3} - \frac{171}{2} + 8

Simplify

\frac{49}{3} - \frac{171}{2} + 8 : - \frac{367}{6}

= - \frac{367}{6}

\int_{0}^{1} \frac{1}{1 + 8 x} d x

\int_{0}^{2} e^{- x^{3}} d x

\int_{3}^{5} \frac{5}{( 2 x + 1 ) ( x - 2 )} d x

\int_{0}^{0.4} cos (x) + ln (x + 1) d x

\int_{1}^{e} (ln (x))^{5} d x

What is the integral from 1 to 2 of (7x^2-57x+8) ?
The integral from 1 to 2 of (7x^2-57x+8) is -367/6