What is the integral from 0 to 2pi of cos^2(x)sin(x) ?

The integral from 0 to 2pi of cos^2(x)sin(x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of cos^2(x)sin(x)

\int_{0}^{2 π} cos^{2} (x) sin (x) d x

0

Solution steps

\int_{0}^{2 π} cos^{2} (x) sin (x) d x

Compute the indefinite integral:

\int cos^{2} (x) sin (x) d x = - \frac{cos ^{3} ( x )}{3} + C

Compute the boundaries:

\int_{0}^{2 π} cos^{2} (x) sin (x) d x = - \frac{1}{3} - (- \frac{1}{3})

= - \frac{1}{3} - (- \frac{1}{3})

Simplify

= 0

\int_{1}^{3} x^{3} - 1 d x

\int_{1}^{3} e^{x} ln (x) d x

\int_{1}^{3} \frac{2}{x} + 1 d x

\int_{0}^{r} (b r^{2} + cr) 2 π r d r

\int_{0}^{\frac{π}{3}} (cos (x) + sec (x))^{2} d x

What is the integral from 0 to 2pi of cos^2(x)sin(x) ?
The integral from 0 to 2pi of cos^2(x)sin(x) is 0