What is the derivative of f(x)=sqrt(x+6) ?

The derivative of f(x)=sqrt(x+6) is 1/(2sqrt(x+6))

What is the first derivative of f(x)=sqrt(x+6) ?

The first derivative of f(x)=sqrt(x+6) is 1/(2sqrt(x+6))

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derivative of

f (x) = x + 6

\frac{1}{2 x + 6}

Solution steps

\frac{d}{d x} (x + 6)

Apply the chain rule:

\frac{1}{2 x + 6} \frac{d}{d x} (x + 6)

= \frac{1}{2 x + 6} \frac{d}{d x} (x + 6)

\frac{d}{d x} (x + 6) = 1

= \frac{1}{2 x + 6} \cdot 1

Simplify

= \frac{1}{2 x + 6}

n = 1 \sum \infty n^{\frac{3}{4}}

\frac{d}{d x} (4 x^{3} arcsec (x))

\int 90 x^{2} sin (2 + 6 x^{3}) d x

1 - y^{2} d x - 1 - x^{2} d y = 0

f (x) = cos (\frac{x}{3})

What is the derivative of f(x)=sqrt(x+6) ?
The derivative of f(x)=sqrt(x+6) is 1/(2sqrt(x+6))
What is the first derivative of f(x)=sqrt(x+6) ?
The first derivative of f(x)=sqrt(x+6) is 1/(2sqrt(x+6))