What is the integral from 0 to 2pi of (sin(8x))^2 ?

The integral from 0 to 2pi of (sin(8x))^2 is 0

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integral from 0 to 2pi of (sin(8x))^2

\int_{0}^{2 π} (sin (8 x))^{2} d x

0

Solution steps

\int_{0}^{2 π} (sin (8 x))^{2} d x

Evaluating using numerical calculation methods

= 0

\int_{1}^{4} \frac{9}{2 x - 1} d x

\int_{5}^{20} \frac{5}{x + 8} d x

\int_{0}^{1} \frac{x ^{3} + 4}{x ( x + 1 )} d x

\int_{0}^{0.5} x^{3} + 1 d x

\int_{0}^{π} x^{2} cos (x + 1) d x

What is the integral from 0 to 2pi of (sin(8x))^2 ?
The integral from 0 to 2pi of (sin(8x))^2 is 0