What is the sum from n=1 to infinity of n/(7^n) ?

The sum from n=1 to infinity of n/(7^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of n/(7^n)

n = 1 \sum \infty \frac{n}{7 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n}{7 ^{n}}

Apply Series Ratio Test:

converges

= converges

x \to 0 lim (\frac{( ln ( 1 + x ) )}{x})

\int (3 x - 2)^{4} d x

x^{2}, 0

f (x) = \frac{( 1 - 4 x )}{1 + 4 x}

t \frac{d y}{d t} = 4 y

What is the sum from n=1 to infinity of n/(7^n) ?
The sum from n=1 to infinity of n/(7^n) is converges