What is the integral from 3 to infinity of 1/(ln(x)) ?

The integral from 3 to infinity of 1/(ln(x)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 3 to infinity of 1/(ln(x))

\int_{3}^{\infty} \frac{1}{ln ( x )} d x

diverges

Solution steps

\int_{3}^{\infty} \frac{1}{ln ( x )} d x

Compute the indefinite integral:

\int \frac{1}{ln ( x )} d x = Ei (ln (x)) + C

Compute the boundaries:

\int_{3}^{\infty} \frac{1}{ln ( x )} d x =

diverges

= diverges

\int_{- 1}^{3} (- x^{3} - 5 x + 1) d x

\int_{1}^{2} (ln (4 x))^{2} d x

\int_{0}^{1} (x^{4} + 5)^{3} x^{3} d x

\int_{1}^{4} 1 + 4 x^{2} d x

\int_{1}^{3} \frac{y + 4}{y - 4} d y

What is the integral from 3 to infinity of 1/(ln(x)) ?
The integral from 3 to infinity of 1/(ln(x)) is diverges