What is the integral from 0 to 4 of 1/(sqrt(x^3)) ?

The integral from 0 to 4 of 1/(sqrt(x^3)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 1/(sqrt(x^3))

\int_{0}^{4} \frac{1}{x ^{3}} d x

diverges

Solution steps

\int_{0}^{4} \frac{1}{x ^{3}} d x

Apply exponent rule:

(a^{n})^{m} = a^{n \cdot m}

x^{3} = x^{\frac{3}{2}}

= \int_{0}^{4} \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: [- \frac{2}{x}]_{0}^{4}

= [- \frac{2}{x}]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\int_{0}^{\frac{π}{5}} x cos (5 x) d x

\int_{0}^{7} tan (x) d x

\int_{- 1}^{2} (x - 1)^{2} d x

\int_{0}^{\frac{π}{2}} sin (x - y) d y

\int_{0}^{1} x^{9} e^{- x} d x

What is the integral from 0 to 4 of 1/(sqrt(x^3)) ?
The integral from 0 to 4 of 1/(sqrt(x^3)) is diverges