What is the integral from 0 to 1 of [ y/(e^{2y)}] ?

The integral from 0 to 1 of [ y/(e^{2y)}] is -3/(4e^2)+1/4

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integral from 0 to 1 of [ y/(e^{2y)}]

\int_{0}^{1} [\frac{y}{e ^{2 y}}] d y

- \frac{3}{4 e ^{2}} + \frac{1}{4}

Decimal Notation

0.14849 \dots

Solution steps

\int_{0}^{1} \frac{y}{e ^{2 y}} d y

Apply Integration By Parts

: [- \frac{1}{2} e^{- 2 y} y - \int - \frac{1}{2} e^{- 2 y} d y]_{0}^{1}

= [- \frac{1}{2} e^{- 2 y} y - \int - \frac{1}{2} e^{- 2 y} d y]_{0}^{1}

\int - \frac{1}{2} e^{- 2 y} d y = \frac{1}{4} e^{- 2 y}

= [- \frac{1}{2} e^{- 2 y} y - \frac{1}{4} e^{- 2 y}]_{0}^{1}

Compute the boundaries:

- \frac{3}{4 e ^{2}} + \frac{1}{4}

= - \frac{3}{4 e ^{2}} + \frac{1}{4}

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What is the integral from 0 to 1 of [ y/(e^{2y)}] ?
The integral from 0 to 1 of [ y/(e^{2y)}] is -3/(4e^2)+1/4