What is the integral from 1 to 13 of (6x^2+3x-2) ?

The integral from 1 to 13 of (6x^2+3x-2) is 4620

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integral from 1 to 13 of (6x^2+3x-2)

\int_{1}^{13} (6 x^{2} + 3 x - 2) d x

4620

Solution steps

\int_{1}^{13} 6 x^{2} + 3 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{13} 6 x^{2} d x + \int_{1}^{13} 3 x d x - \int_{1}^{13} 2 d x

\int_{1}^{13} 6 x^{2} d x = 4392

\int_{1}^{13} 3 x d x = 252

\int_{1}^{13} 2 d x = 24

= 4392 + 252 - 24

Simplify

= 4620

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What is the integral from 1 to 13 of (6x^2+3x-2) ?
The integral from 1 to 13 of (6x^2+3x-2) is 4620