What is the sum from n=0 to infinity of (e/(8pi))^n ?

The sum from n=0 to infinity of (e/(8pi))^n is (8pi)/(8pi-e)

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sum from n=0 to infinity of (e/(8pi))^n

n = 0 \sum \infty (\frac{e}{8 π})^{n}

\frac{8 π}{8 π - e}

Solution steps

n = 0 \sum \infty (\frac{e}{8 π})^{n}

Apply Series Geometric Test:

\frac{8 π}{8 π - e}

= \frac{8 π}{8 π - e}

\int \frac{ln ( 2 x )}{x ln ( x )} d x

x \to 1 lim (\frac{1 - x ^{2}}{x - 1})

y = \frac{2}{x - 8} (10.1)

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{3}}}

What is the sum from n=0 to infinity of (e/(8pi))^n ?
The sum from n=0 to infinity of (e/(8pi))^n is (8pi)/(8pi-e)