What is the integral from-1 to 1 of (10)/(x^4) ?

The integral from-1 to 1 of (10)/(x^4) is diverges

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integral from-1 to 1 of (10)/(x^4)

\int_{- 1}^{1} \frac{10}{x ^{4}} d x

diverges

Solution steps

\int_{- 1}^{1} \frac{10}{x ^{4}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{10}{x ^{4}} d x + \int_{0}^{1} \frac{10}{x ^{4}} d x

\int_{- 1}^{0} \frac{10}{x ^{4}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{7} 10 x ln (x) d x

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\int_{20}^{30} (3 x + 4)^{2} d x

\int_{0}^{\frac{π}{4}} 1 d x

\int_{- 4}^{0} - x d x

What is the integral from-1 to 1 of (10)/(x^4) ?
The integral from-1 to 1 of (10)/(x^4) is diverges