What is the integral from-infinity to 3 of θe^θ ?

The integral from-infinity to 3 of θe^θ is 2e^3

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integral from-infinity to 3 of θe^θ

\int_{- \infty}^{3} θ e^{θ} d θ

2 e^{3}

Decimal Notation

40.17107 \dots

Solution steps

\int_{- \infty}^{3} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{3} θ e^{θ} d θ = 2 e^{3} - 0

= 2 e^{3} - 0

Simplify

= 2 e^{3}

\int_{- \infty}^{- 2} θ e^{θ} d θ

\int_{0}^{1} x^{2} e^{- 14 x} d x

\int_{1}^{3} (y - 2)^{2} d y

\int_{0}^{1} x^{2} e^{- 9 x} d x

\int_{1}^{4} x x + 1 d x

What is the integral from-infinity to 3 of θe^θ ?
The integral from-infinity to 3 of θe^θ is 2e^3