What is the derivative of sqrt(x)-7\sqrt[3]{x} ?

The derivative of sqrt(x)-7\sqrt[3]{x} is 1/(2sqrt(x))-7/(3x^{2/3)}

What is the first derivative of sqrt(x)-7\sqrt[3]{x} ?

The first derivative of sqrt(x)-7\sqrt[3]{x} is 1/(2sqrt(x))-7/(3x^{2/3)}

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Popular >

\frac{1}{2 x} - \frac{7}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - \frac{7}{3 x ^{\frac{2}{3}}}

\frac{3 ( 1 - 4 x )}{58 ( x ^{2} + 9 )}

sin (ln (cos (t)))

\int x^{2} 6 x + 6 d x

f (x) = x^{3} + x + 5, at x = - 2

(2 x^{3} - x^{2} y) + (2 x^{2} y - x^{3}) y^{^{'}} = 0

What is the derivative of sqrt(x)-7\sqrt[3]{x} ?
The derivative of sqrt(x)-7\sqrt[3]{x} is 1/(2sqrt(x))-7/(3x^{2/3)}
What is the first derivative of sqrt(x)-7\sqrt[3]{x} ?
The first derivative of sqrt(x)-7\sqrt[3]{x} is 1/(2sqrt(x))-7/(3x^{2/3)}