What is the integral from 0 to 81 of 1/(\sqrt[4]{x)} ?

The integral from 0 to 81 of 1/(\sqrt[4]{x)} is 36

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integral from 0 to 81 of 1/(\sqrt[4]{x)}

36

Solution steps

Apply the Power Rule

: [\frac{4}{3} x^{\frac{3}{4}}]_{0}^{81}

= [\frac{4}{3} x^{\frac{3}{4}}]_{0}^{81}

Compute the boundaries:

36

= 36

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What is the integral from 0 to 81 of 1/(\sqrt[4]{x)} ?
The integral from 0 to 81 of 1/(\sqrt[4]{x)} is 36