What is the integral from-1 to 2 of (3sqrt(x)-3) ?

The integral from-1 to 2 of (3sqrt(x)-3) is 4sqrt(2)+2i-9

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integral from-1 to 2 of (3sqrt(x)-3)

\int_{- 1}^{2} (3 x - 3) d x

42 + 2 i - 9

Solution steps

\int_{- 1}^{2} 3 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 3 x d x - \int_{- 1}^{2} 3 d x

\int_{- 1}^{2} 3 x d x = 42 + 2 i

\int_{- 1}^{2} 3 d x = 9

= 42 + 2 i - 9

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\int_{0}^{2 π} 1 + cos (x) d x

\int_{0}^{1} 3^{x} e^{x} sin (x) d x

\int_{3}^{5} - x^{2} + 7 x - 10 d x

\int_{0}^{2 π} cos^{2} (θ) sin (θ) d θ

What is the integral from-1 to 2 of (3sqrt(x)-3) ?
The integral from-1 to 2 of (3sqrt(x)-3) is 4sqrt(2)+2i-9