What is the integral from 0 to pi/6 of sqrt(cos(x)) ?

The integral from 0 to pi/6 of sqrt(cos(x)) is 2\E((pi/6)/2 \vert 2)-2\E(0*2\vert)

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integral from 0 to pi/6 of sqrt(cos(x))

\int_{0}^{\frac{π}{6}} cos (x) d x

2 E (\frac{\frac{π}{6}}{2} ∣2) - 2 E (0 \cdot 2∣)

Solution steps

\int_{0}^{\frac{π}{6}} cos (x) d x

Use the nonelementary integral:

\int cos (x) d x = 2 E (\frac{x}{2} ∣ 2)

= [2 E (\frac{x}{2} ∣ 2)]_{0}^{\frac{π}{6}}

Compute the boundaries:

2 E (\frac{\frac{π}{6}}{2} ∣ 2) - 2 E (0 \cdot 2∣)

= 2 E (\frac{\frac{π}{6}}{2} ∣ 2) - 2 E (0 \cdot 2∣)

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What is the integral from 0 to pi/6 of sqrt(cos(x)) ?
The integral from 0 to pi/6 of sqrt(cos(x)) is 2\E((pi/6)/2 \vert 2)-2\E(0*2\vert)