What is the integral from 0 to (3pi)/4 of sin(x) ?

The integral from 0 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to (3pi)/4 of sin(x)

\int_{0}^{\frac{3 π}{4}} sin (x) d x

\frac{1}{2} + 1

Decimal Notation

1.70710 \dots

Solution steps

\int_{0}^{\frac{3 π}{4}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{3 π}{4}}

Compute the boundaries:

\frac{1}{2} + 1

= \frac{1}{2} + 1

\int_{3}^{4} \frac{1}{x} lo g_{e} (x) d x

\int_{- \infty}^{0} x e^{2 + 3 x} d x

\int_{3}^{5} \frac{( x + 2 ) ^{2}}{x - 2} d x

\int_{4}^{5} \frac{x}{x ^{2} - 5 x + 6} d x

\int_{6}^{\infty} - x e^{- x} d x

What is the integral from 0 to (3pi)/4 of sin(x) ?
The integral from 0 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1