What is the derivative of x^3-3x^2+4x-1 ?

The derivative of x^3-3x^2+4x-1 is 3x^2-6x+4

What is the first derivative of x^3-3x^2+4x-1 ?

The first derivative of x^3-3x^2+4x-1 is 3x^2-6x+4

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\frac{d}{d x} (x^{3} - 3 x^{2} + 4 x - 1)

3 x^{2} - 6 x + 4

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 3 x^{2} - 6 x + 4 - 0

Simplify

= 3 x^{2} - 6 x + 4

y^{^{'}} + sin (t) y = sin (t)

\frac{d}{d x} (\frac{1}{2} x^{\frac{3}{2}})

\int \frac{3 t + 2}{t + 1} d t

\frac{d}{d x} (e)

\frac{12800}{1 + 10 e ^{- 0.5 x}}

What is the derivative of x^3-3x^2+4x-1 ?
The derivative of x^3-3x^2+4x-1 is 3x^2-6x+4
What is the first derivative of x^3-3x^2+4x-1 ?
The first derivative of x^3-3x^2+4x-1 is 3x^2-6x+4